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Latihan Soal Eksponen 2

By Dadang Nasution November 25, 2018 Post a Comment

Assalamu'alaikum Warahmatullahi Wabarakatuh

Yuk kita latihan sedikit-demi sedikit hehe :D..

Disini saya mau share soal Eksponen nih.

Dibawah ada kunci jawabannya kok.

Semoga bermanfaat :)

$\frac{ab\sqrt{c}}{\sqrt{a}\sqrt{bc}}=...$
a. $\sqrt{ab}$
b. $\sqrt{\frac{ac}{b}}$
c. $\sqrt{\frac{bc}{a}}$
d. $\sqrt{c}$
e. $\sqrt{b}$
$\frac{\sqrt{a}\sqrt[3]{bc}}{\sqrt[6]{a^{2}b^{4}c^{3}}}=...$
a. $\sqrt{\frac{ac^{3}}{b^{2}}}$
b. $\sqrt[3]{\frac{ac}{b}}$
c. $\sqrt[6]{\frac{a}{b^{2}c}}$
d. $\sqrt[4]{abc}$
e. $\sqrt[3]{abc}$
$\left ( \frac{a^{\frac{2}{3}}}{b^{\frac{1}{2}}} \right )^{-1}.\left ( a^{\frac{2}{3}}.b^{\frac{1}{2}}\right )^{2}\div \frac{b^{\frac{1}{2}}}{a^{\frac{1}{3}}}=...$
a. $\sqrt{ab}$
b. $b\sqrt{a}$
c. $ab$
d. $a\sqrt{b}$
e. $\sqrt[3]{ab}$
$\left ( \frac{1}{1+p} \right )^{5}\cdot \left ( \frac{1}{1-p} \right )^{-7}\cdot \left ( \frac{p-1}{1+p} \right )^{-6}=...$
a. $p$
b. $1-p^{2}$
c. $p^{2}-1$
d. $p^{2}+2p+1$
e. $p^{2}-p+1$
Jika $f(x)=2^{x}$ maka $\frac{f(x+3)}{f(x-1)}=...$
a. $f(2)$
b. $f(4)$
c. $f(16)$
d. $f\left ( \frac{x+3}{x-1} \right )$
e. $f(2x+2)$

Apabila ada kesalahan dalam soal maupun jawaban harap tinggalkan komentar di bawah ya :) terima kasih.

KUNCI JAWABAN

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